Strength of Materials |
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Page 110
... Hence BE = d = 1400 = 7 ft . 200 As a preliminary to computing the bending moments , we determine the areas of the shear diagram marked A1 , A2 , A3 , and A4 . A1 = A 2 = ( 3 ) ( - 600 ) ( 7 ) ( 1400 ) = -900 ft - lb = +4900 ft - lb A3 ...
... Hence BE = d = 1400 = 7 ft . 200 As a preliminary to computing the bending moments , we determine the areas of the shear diagram marked A1 , A2 , A3 , and A4 . A1 = A 2 = ( 3 ) ( - 600 ) ( 7 ) ( 1400 ) = -900 ft - lb = +4900 ft - lb A3 ...
Page 203
... Hence , if the triangular area is revolved about the line of zero moment as an axis , we obtain diagram ( d ) . The shaded area of diagram ( d ) is evidently equal to the area of the conventional moment diagram ( e ) obtained by ...
... Hence , if the triangular area is revolved about the line of zero moment as an axis , we obtain diagram ( d ) . The shaded area of diagram ( d ) is evidently equal to the area of the conventional moment diagram ( e ) obtained by ...
Page 481
... Hence , taking moments about the shear center C , we have V1b1 = V2b2 ( b ) Another relation between V1 and V2 may be found from the fact that the two flanges bend as though they were separate beams which have identical radii of ...
... Hence , taking moments about the shear center C , we have V1b1 = V2b2 ( b ) Another relation between V1 and V2 may be found from the fact that the two flanges bend as though they were separate beams which have identical radii of ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ