## Strength of materials |

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Page xiv

Rules of sign have also been simplified by assigning the positive sense to all

quantities to which the adjectives up, above, or similar terms may be applied; for

negative signs, the converse is true. Numerous

detail ...

Rules of sign have also been simplified by assigning the positive sense to all

quantities to which the adjectives up, above, or similar terms may be applied; for

negative signs, the converse is true. Numerous

**illustrative problems**show indetail ...

Page 264

These values are summarized in Table 7-2. In the following problems we show

how these general values arc superposed to solve design problems involving

various combinations of loads.

These values are summarized in Table 7-2. In the following problems we show

how these general values arc superposed to solve design problems involving

various combinations of loads.

**ILLUSTRATIVE PROBLEMS**746. Determine the ...Page 546

In the

geometric elements can be taken from the results of the problems in Art. A-5;

these are summarized in Table A-1. The properties of a geometric shape that is

the ...

In the

**illustrative problems**which follow, the values of the moments of inertia forgeometric elements can be taken from the results of the problems in Art. A-5;

these are summarized in Table A-1. The properties of a geometric shape that is

the ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero