## Strength of materials |

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Page 60

These relations, resulting from considering the equilibrium between externally

applied loads and the internal resisting forces over an exploratory section, are

called the equations of equilibrium. 3. Be sure that the

...

These relations, resulting from considering the equilibrium between externally

applied loads and the internal resisting forces over an exploratory section, are

called the equations of equilibrium. 3. Be sure that the

**solution**of the equations in...

Page 258

Comparison with the

Eqs (d) and (e) used there are identical with Eqs. (a) and (b) here. On the other

hand, comparison with the superposition

Comparison with the

**solution**by double integration on page 250 discloses thatEqs (d) and (e) used there are identical with Eqs. (a) and (b) here. On the other

hand, comparison with the superposition

**solution**on page 252 discloses that its ...Page 308

that was described in Prob. 874 for free ends on two spans. It is inconvenient to

treat a free end as fixed, carry moment over to it, and then release it again.

**Solution**: There are two**solutions**. The first, in (a), involves the same procedurethat was described in Prob. 874 for free ends on two spans. It is inconvenient to

treat a free end as fixed, carry moment over to it, and then release it again.

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero