Strength of Materials |
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Page 60
... solution of the equations in steps 1 and 2 is consistent with the loading conditions at the surface of the body . This is known as satisfying the boundary conditions . In the theory of elasticity , it is shown that a solution satisfying ...
... solution of the equations in steps 1 and 2 is consistent with the loading conditions at the surface of the body . This is known as satisfying the boundary conditions . In the theory of elasticity , it is shown that a solution satisfying ...
Page 258
... solution by double integration on page 250 discloses that Eqs ( d ) and ( e ) used there are identical with Eqs . ( a ) and ( b ) here . On the other hand , comparison with the superposition solution on page 252 discloses that its ...
... solution by double integration on page 250 discloses that Eqs ( d ) and ( e ) used there are identical with Eqs . ( a ) and ( b ) here . On the other hand , comparison with the superposition solution on page 252 discloses that its ...
Page 308
Ferdinand Leon Singer. Solution : There are two solutions . The first , in ( a ) , involves the same pro- cedure that was described in Prob . 874 for free ends on two spans . It is incon- venient to treat a free end as fixed , carry ...
Ferdinand Leon Singer. Solution : There are two solutions . The first , in ( a ) , involves the same pro- cedure that was described in Prob . 874 for free ends on two spans . It is incon- venient to treat a free end as fixed , carry ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ