## Strength of materials |

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Results 1-3 of 42

Page 283

816.

. See Fig. P-817. 818. In Prob. 817, determine the changed value of the applied

couple that will cause M2 to become zero. Ans. M = 780 ft-lb counterclockwise ...

816.

**Solve Prob**. 815 if one span is three-fourths the length of the other span. 817. See Fig. P-817. 818. In Prob. 817, determine the changed value of the applied

couple that will cause M2 to become zero. Ans. M = 780 ft-lb counterclockwise ...

Page 310

Ferdinand Leon Singer.

. (1) The cross section may vary from segment to segment and is taken into

account bv computing the — ratio for each segment.* (2) The overhanging end

offers ...

Ferdinand Leon Singer.

**Solution**: This**problem**illustrates two additional concepts. (1) The cross section may vary from segment to segment and is taken into

account bv computing the — ratio for each segment.* (2) The overhanging end

offers ...

Page 416

maximum length of a 10 WF 49 section used as a column to support a central

load of 80,000 lb and an eccentric load of 40,000 lb acting 10 in. off center on the

Y ...

**Solve Prob**. 1138 if the eccentric load is applied on the major axis. 1140. Find themaximum length of a 10 WF 49 section used as a column to support a central

load of 80,000 lb and an eccentric load of 40,000 lb acting 10 in. off center on the

Y ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero