Strength of Materials |
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Page 283
Ferdinand Leon Singer. 816. Solve Prob . 815 if one span is three - fourths the length of the other span . 817. See Fig . P - 817 . 818. In Prob . 817 , determine the changed value of the applied couple that will cause M2 to become zero ...
Ferdinand Leon Singer. 816. Solve Prob . 815 if one span is three - fourths the length of the other span . 817. See Fig . P - 817 . 818. In Prob . 817 , determine the changed value of the applied couple that will cause M2 to become zero ...
Page 310
Ferdinand Leon Singer. Solution : This problem illustrates two additional concepts . ( 1 ) The cross sec- tion may vary from segment to segment and is taken into account by computing the I ratio for each segment . * ( 2 ) The overhanging ...
Ferdinand Leon Singer. Solution : This problem illustrates two additional concepts . ( 1 ) The cross sec- tion may vary from segment to segment and is taken into account by computing the I ratio for each segment . * ( 2 ) The overhanging ...
Page 416
... Solve Prob . 1140 if the eccentric load is reduced to 20,000 lb. 1142. A steel column 30 ft long has the section specified in Prob . 1124. It carries an axial load of 100,000 lb. Using the AASHO formula with pinned ends and Eq . ( 11-21 ) ...
... Solve Prob . 1140 if the eccentric load is reduced to 20,000 lb. 1142. A steel column 30 ft long has the section specified in Prob . 1124. It carries an axial load of 100,000 lb. Using the AASHO formula with pinned ends and Eq . ( 11-21 ) ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ