Strength of Materials |
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Page 18
... acting normal to the cutting plane A - A , is resisted by the equal forces P acting on each cut surface of the cylinder wall . Applying a vertical summation of forces , we obtain [ ΣΤ = 0 ] F = pDL = 2P ( 1-4 ) A simpler method of ...
... acting normal to the cutting plane A - A , is resisted by the equal forces P acting on each cut surface of the cylinder wall . Applying a vertical summation of forces , we obtain [ ΣΤ = 0 ] F = pDL = 2P ( 1-4 ) A simpler method of ...
Page 327
... acting at a point is represented by the stresses acting on the faces of the element enclosing the point . As we saw in Art . 9-4 , the stresses change with the inclination of the planes passing through that point ; i.e. , the stresses ...
... acting at a point is represented by the stresses acting on the faces of the element enclosing the point . As we saw in Art . 9-4 , the stresses change with the inclination of the planes passing through that point ; i.e. , the stresses ...
Page 499
... acting in the plane of curvature is reduced to a single force R acting at the cen- troid of the section , plus a bending couple M. The moment of this couple is equivalent to the summa- tion of moments about the centroi- dal axis of the ...
... acting in the plane of curvature is reduced to a single force R acting at the cen- troid of the section , plus a bending couple M. The moment of this couple is equivalent to the summa- tion of moments about the centroi- dal axis of the ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ