## Strength of materials |

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Page 40

A solid

Compute the internal diameter of the steel tube so that no contact pressure exists

when the

A solid

**aluminum**shaft of 3-in. diameter fits concentrically in a hollow steel tube.Compute the internal diameter of the steel tube so that no contact pressure exists

when the

**aluminum**shaft carries an axial compressive load of 84,800 lb.Page 48

-10"- 15"

Fig. P-244 is firmly attached to unyielding supports. Find the stress caused in

each material by applying an axial load P = 44,000 lb. Ans. Sa = 8000 psi; S. =

16,000 ...

-10"- 15"

**Aluminum**.E-l0xl06 ^ =1.5 in.2 Steel £-30xl06 244. The bar shown inFig. P-244 is firmly attached to unyielding supports. Find the stress caused in

each material by applying an axial load P = 44,000 lb. Ans. Sa = 8000 psi; S. =

16,000 ...

Page 56

Determine the temperature rise in Prob. 269 that will cause the bronze to be

stressed to 6000 psi. Ans. 150°F 271. An

cylinder are centered and secured between two rigid slabs by tightening two

steel bolts, ...

Determine the temperature rise in Prob. 269 that will cause the bronze to be

stressed to 6000 psi. Ans. 150°F 271. An

**aluminum**cylinder and a bronzecylinder are centered and secured between two rigid slabs by tightening two

steel bolts, ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero