## Strength of Materials |

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Page 444

A 4 by 4 by §

42,000 lb applied along its centroidal axis, (a) Determine the lengths of side fillet

welds required at the heel and toe of the

A 4 by 4 by §

**angle**is to be welded to a gusset plate. The**angle**carries a load of42,000 lb applied along its centroidal axis, (a) Determine the lengths of side fillet

welds required at the heel and toe of the

**angle**. The weld at the heel is to be the ...Page 524

What will be the residual

at each end of a straight shaft 3 ft long and J in. in diameter is bent at right

to the shaft. Determine the

What will be the residual

**angle**of twist? Ans. 6, 17 LS^ 24 Gr 1421. A 6-in. lengthat each end of a straight shaft 3 ft long and J in. in diameter is bent at right

**angles**to the shaft. Determine the

**angle**through which one of the bent ends must be ...Page 561

The

between the two axes of inertia represented by these two radii. The rotational

sense of this

between the ...

The

**angle**between any two radii on Mohr's circle is double the actual**angle**between the two axes of inertia represented by these two radii. The rotational

sense of this

**angle**corresponds to the rotational sense of the actual**angle**between the ...

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### Common terms and phrases

acting actual allowable angle applied assumed axes axis beam shown bending bending moment cantilever carries caused centroid circle CN CN column compressive compressive stress compute concentrated consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia lb/ft length limit load loaded as shown material maximum method midspan moments negative neutral axis obtain occurs plane plate positive Prob PROBLEMS produce reaction reference relation resisting respect restrained resultant rivet segment shear diagram shearing stress shown in Fig shows simply supported slope Solution Solve span steel strain strength supported Table tangent tensile thickness varies vertical wall weight weld yield zero