## Strength of materials |

### From inside the book

Results 1-3 of 76

Page 352

between OA and its normal OB, which defines the shearing strain for an element

located 0° from the X-Y axes, becomes Tat = P — j8' = ex(2 sin 6 cos 6) — e„(2

sin 6 cos 0) + 7x„(cos2 0 — sin2 0) which, in terms of the double

between OA and its normal OB, which defines the shearing strain for an element

located 0° from the X-Y axes, becomes Tat = P — j8' = ex(2 sin 6 cos 6) — e„(2

sin 6 cos 0) + 7x„(cos2 0 — sin2 0) which, in terms of the double

**angle**20, ...Page 444

As a result, the maximum size of a fillet weld at the square edge of a plate is

limited to ^g in. less than the plate thickness; a weld at the rounded edges of

flanges or the toe of an

As a result, the maximum size of a fillet weld at the square edge of a plate is

limited to ^g in. less than the plate thickness; a weld at the rounded edges of

flanges or the toe of an

**angle**may be three-fourths the thickness of the edge.Page 446

A 6 by 4 by £

with the plate. If the

axis, what lengths of j^-in. side fillet welds will be required along the toe and heel

...

A 6 by 4 by £

**angle**is to be welded to a gusset plate with the 6-in. leg in contactwith the plate. If the

**angle**carries a load of 75,000 lb applied along ite centroidalaxis, what lengths of j^-in. side fillet welds will be required along the toe and heel

...

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

### Common terms and phrases

allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero