## Strength of Materials |

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Page 70

Solve Prob . 313 if the shaft rotates at 126 rpm with 30 hp taken off at A , 75 hp

removed at C , and 105 hp

has 100 hp

removed .

Solve Prob . 313 if the shaft rotates at 126 rpm with 30 hp taken off at A , 75 hp

removed at C , and 105 hp

**applied**at B . 315 . A 16 - ft shaft rotating at 126 rpmhas 100 hp

**applied**at a gear that is 6 ft from the left end where 30 hp areremoved .

Page 462

Of these several theories of failure , experimental work shows best agreement

with the Mises yield theory when

the maximum shear theory also gives good agreement . For rupture in brittle ...

Of these several theories of failure , experimental work shows best agreement

with the Mises yield theory when

**applied**to ductile materials . For such materialsthe maximum shear theory also gives good agreement . For rupture in brittle ...

Page 523

If a load P = 150 , 000 lb is

force in each bar . Ans . Pa = - 8100 lb ; P . = 16 , 200 lb 1416 . The bar shown in

Fig . P - 1416 is firmly attached to rigid supports . The yield strengths for steel and

...

If a load P = 150 , 000 lb is

**applied**and then removed , determine the residualforce in each bar . Ans . Pa = - 8100 lb ; P . = 16 , 200 lb 1416 . The bar shown in

Fig . P - 1416 is firmly attached to rigid supports . The yield strengths for steel and

...

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### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

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### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero