## Strength of materials |

### From inside the book

Results 1-3 of 47

Page 553

However, with respect to a new set of

counterclockwise from the original set of

The new coordinates of dA are x' = y and y' = —x, so that with respect to the new ...

However, with respect to a new set of

**axes**, marked X' and Y' and rotated 90°counterclockwise from the original set of

**axes**, the area is in the fourth quadrant.The new coordinates of dA are x' = y and y' = —x, so that with respect to the new ...

Page 556

A-18 with respect to the indicated X and Y

be considered composed of a 5 by 1 in. rectangle plus an 8 by 1 in. rectangle. For

the first rectangle, the centroidal

A-18 with respect to the indicated X and Y

**axes**. Solution: The angle section canbe considered composed of a 5 by 1 in. rectangle plus an 8 by 1 in. rectangle. For

the first rectangle, the centroidal

**axes**parallel to the X and Y**axes**are**axes**of ...Page 558

P-A37 with respect to the given A* and Y

A38. A38. Use the result of Prob. A37 to determine the product of inertia of the

shaded area described in Fig. P-A38 with respect to the given X and }"

Ans.

P-A37 with respect to the given A* and Y

**axes**. Ans. Pxy = - Fig. P-A37. Fig. P-A38. A38. Use the result of Prob. A37 to determine the product of inertia of the

shaded area described in Fig. P-A38 with respect to the given X and }"

**axes**. r*Ans.

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

### Common terms and phrases

allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero