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Page 143
... beam with 30.8 in.3 , which is also satisfactory as well as being lighter . The 12 - in . group lists a 12 WF 27 beam with Z 34.1 in.3 ; this is the best one , because the lightest suitable beam in the next ( 14 - in . ) group weighs ...
... beam with 30.8 in.3 , which is also satisfactory as well as being lighter . The 12 - in . group lists a 12 WF 27 beam with Z 34.1 in.3 ; this is the best one , because the lightest suitable beam in the next ( 14 - in . ) group weighs ...
Page 146
... beam is 4.8 lb heavier per foot than the WF beam , which indicates one reason for the latter's popularity . After you have used the tables of properties of structural shapes several times to select the proper size of a beam and are ...
... beam is 4.8 lb heavier per foot than the WF beam , which indicates one reason for the latter's popularity . After you have used the tables of properties of structural shapes several times to select the proper size of a beam and are ...
Page 268
... beam that will support these loads without exceeding a flexural stress of 18,000 psi . Compute the midspan deflection of this beam if E = 30 X 106 psi . Ans . 8 ... beam deflections studied in Chapter 6 268 [ Chap . 7 Restrained Beams.
... beam that will support these loads without exceeding a flexural stress of 18,000 psi . Compute the midspan deflection of this beam if E = 30 X 106 psi . Ans . 8 ... beam deflections studied in Chapter 6 268 [ Chap . 7 Restrained Beams.
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ