## Strength of materials |

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Page 100

= —3480 ft-lb 405.

Br ]c ' B 200 lb/ ft 3' 6' 300 lb/ ft 400 lb/ ft «1 Fig. P-406. 4' «2 Fig. P-405. 406.

**Beam loaded**as shown in Fig. P-404. Ans. Mac = 3600 — 230x — 30x2; Max. M= —3480 ft-lb 405.

**Beam loaded**as shown in Fig. P-405. Ans. Max. M = 3456 ft-lbBr ]c ' B 200 lb/ ft 3' 6' 300 lb/ ft 400 lb/ ft «1 Fig. P-406. 4' «2 Fig. P-405. 406.

Page 119

as shown in Fig. P-443. Ans. Max. M = 4720 ft-lb 120 lb/ ft- 60 lb/ft 1200lb 72 lb/ ft

50 lb/ft 6' Fig. P-444. J t- *2 90 lb/ft 6' 180 lb/ ft Fig. P-445. 446.

**Beam loaded**as shown in Fig. P-442. Ans. Max. M = 1267 ft-lb 443.**Beam loaded**as shown in Fig. P-443. Ans. Max. M = 4720 ft-lb 120 lb/ ft- 60 lb/ft 1200lb 72 lb/ ft

50 lb/ft 6' Fig. P-444. J t- *2 90 lb/ft 6' 180 lb/ ft Fig. P-445. 446.

**Beam loaded**as ...Page 207

Ferdinand Leon Singer. PROBLEMS For each of the beams in the following

problems, compute the moment of area of the M diagram between the reactions

about both the left and the right reaction. 624.

624.

Ferdinand Leon Singer. PROBLEMS For each of the beams in the following

problems, compute the moment of area of the M diagram between the reactions

about both the left and the right reaction. 624.

**Beam loaded**as shown in Fig. P-624.

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero