## Strength of materials |

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Page 96

We have been careful to assign plus signs to V and M

loads, and minus signs to V and M

be consistent in assigning a plus sign to any upward quantity and a minus sign to

...

We have been careful to assign plus signs to V and M

**caused**by upward-actingloads, and minus signs to V and M

**caused**by downward-acting loads. We shallbe consistent in assigning a plus sign to any upward quantity and a minus sign to

...

Page 200

The resultant bending moment at any section

algebraic sum of the bending moments at that section

acting separately. This statement is expressed algebraically by M = (XM)L = (2M)

« ...

The resultant bending moment at any section

**caused**by any load system is thealgebraic sum of the bending moments at that section

**caused**by each loadacting separately. This statement is expressed algebraically by M = (XM)L = (2M)

« ...

Page 302

8- 19a is perfectly restrained at A and C and simply supported at B. Assume that

at B the beam is temporarily locked or rigidified against the rotation

loads P and Q. Under these conditions, segments AB and BC will act as fixed ...

8- 19a is perfectly restrained at A and C and simply supported at B. Assume that

at B the beam is temporarily locked or rigidified against the rotation

**caused**by theloads P and Q. Under these conditions, segments AB and BC will act as fixed ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero