## Strength of Materials |

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Page 7

about the X axis, we could similarly show that y defines the y coordinate of C. We

conclude that a uniform stress distribution is obtained only when the resultant of

the applied loads passes through the

about the X axis, we could similarly show that y defines the y coordinate of C. We

conclude that a uniform stress distribution is obtained only when the resultant of

the applied loads passes through the

**centroid**of that surface. It does not follow, ...Page 480

... N.A. located a distance e from the center of the web is the shear center for the

channel. h-6 3 g 1.1 H H H H H Fig. 13-20. Fig. 13-21. — In a section having axes

of symmetry, the shear center C cides with the

... N.A. located a distance e from the center of the web is the shear center for the

channel. h-6 3 g 1.1 H H H H H Fig. 13-20. Fig. 13-21. — In a section having axes

of symmetry, the shear center C cides with the

**centroid**O. In a WF beam or an ...Page 482

It lies between the

the larger moment of inertia. When there is only one flange, as in the T section in

Fig. 13-23, if the bending resistance of the web is again assumed to be negligible

...

It lies between the

**centroid**of the section and the**centroid**of the flange that hasthe larger moment of inertia. When there is only one flange, as in the T section in

Fig. 13-23, if the bending resistance of the web is again assumed to be negligible

...

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### Common terms and phrases

acting actual allowable angle applied assumed axes axis beam shown bending bending moment cantilever carries caused centroid circle CN CN column compressive compressive stress compute concentrated consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia lb/ft length limit load loaded as shown material maximum method midspan moments negative neutral axis obtain occurs plane plate positive Prob PROBLEMS produce reaction reference relation resisting respect restrained resultant rivet segment shear diagram shearing stress shown in Fig shows simply supported slope Solution Solve span steel strain strength supported Table tangent tensile thickness varies vertical wall weight weld yield zero