## Strength of Materials |

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Page 372

The

conventionally denoted by the symbol d , and the location of the neutral axis is

specified as being a fractional part k of this

and n ...

The

**distance**from the top of the beam to the center of the reinforcing steel isconventionally denoted by the symbol d , and the location of the neutral axis is

specified as being a fractional part k of this

**distance**. If the quantities b , d , Ag ,and n ...

Page 539

Each differential element of area dA will then be the same

axis of inertia . The moment of inertia is given by I = Spa dA = kas dA = Ak2

because each differential element has the same moment arm . The strip may be

placed ...

Each differential element of area dA will then be the same

**distance**k from theaxis of inertia . The moment of inertia is given by I = Spa dA = kas dA = Ak2

because each differential element has the same moment arm . The strip may be

placed ...

Page 540

( a ) the equation [ I = Sp2 dA ] Iz = S ( y + d ) 2 dA = Sy2 dA + 2d SydA + d ' S DA

The d is written outside the integral sign because it is a constant that represents

the

) ...

( a ) the equation [ I = Sp2 dA ] Iz = S ( y + d ) 2 dA = Sy2 dA + 2d SydA + d ' S DA

The d is written outside the integral sign because it is a constant that represents

the

**distance**separating the axes . The second of the right - hand terms in Eq . ( a) ...

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### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

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### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero