## Strength of Materials |

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Page 197

or d6 = -j ds (a) In most practical cases the

error is made in assuming the length ds to equal its projection dx. With this

assumption, we obtain dd = jjdx (b) It is evident that tangents drawn to the

or d6 = -j ds (a) In most practical cases the

**elastic curve**is so flat that no seriouserror is made in assuming the length ds to equal its projection dx. With this

assumption, we obtain dd = jjdx (b) It is evident that tangents drawn to the

**elastic****curve**...Page 208

P-630, compute the value of (Area)xB-Ix- From this result determine whether the

tangent drawn to the

to Eq. (6-5) and Fig. 6-10. Ans. (\rea.)AB-^A = 2700lb-ft3; slope is up to right 63 1.

P-630, compute the value of (Area)xB-Ix- From this result determine whether the

tangent drawn to the

**elastic curve**at B slopes up or down to the right. Hint: Referto Eq. (6-5) and Fig. 6-10. Ans. (\rea.)AB-^A = 2700lb-ft3; slope is up to right 63 1.

Page 221

Ferdinand Leon Singer. 150 lb A 4' 301b F\_ D. «, ^ Elastic 'A/C 6 -900 ft-lb Fig. 6-

25. The positive value of Iaic means that .4 on the

reference tangent at C. Hence the reference tangent at C slopes down to the left,

...

Ferdinand Leon Singer. 150 lb A 4' 301b F\_ D. «, ^ Elastic 'A/C 6 -900 ft-lb Fig. 6-

25. The positive value of Iaic means that .4 on the

**elastic curve**lies above thereference tangent at C. Hence the reference tangent at C slopes down to the left,

...

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acting actual allowable angle applied assumed axes axis beam shown bending bending moment cantilever carries caused centroid circle CN CN column compressive compressive stress compute concentrated consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia lb/ft length limit load loaded as shown material maximum method midspan moments negative neutral axis obtain occurs plane plate positive Prob PROBLEMS produce reaction reference relation resisting respect restrained resultant rivet segment shear diagram shearing stress shown in Fig shows simply supported slope Solution Solve span steel strain strength supported Table tangent tensile thickness varies vertical wall weight weld yield zero