Strength of materials |
From inside the book
Results 1-3 of 49
Page 262
P-735 is only partially restrained at its ends. wL3 The slope at the left end is
directed up to the left, whereas at the right 72EI end the slope is wL3 72EI
directed up to the right. Determine the end moments. 736. The beam shown in
Fig. P-735 is ...
P-735 is only partially restrained at its ends. wL3 The slope at the left end is
directed up to the left, whereas at the right 72EI end the slope is wL3 72EI
directed up to the right. Determine the end moments. 736. The beam shown in
Fig. P-735 is ...
Page 263
In other words, the larger end moment acts at the wall that is closer to the
resultant of any single load. The difference between the end moments Mb and
Ma is balanced by the couple R'L, consisting of the forces R' applied at the ends
of the ...
In other words, the larger end moment acts at the wall that is closer to the
resultant of any single load. The difference between the end moments Mb and
Ma is balanced by the couple R'L, consisting of the forces R' applied at the ends
of the ...
Page 303
the moment will be decreased by the remaining 10 ft-lb of the 30 ft-lb difference
between the FEM at B in Fig. ... With this convention, counterclockwise moments
acting on the beam are considered to be positive, and clockwise end moments ...
the moment will be decreased by the remaining 10 ft-lb of the 30 ft-lb difference
between the FEM at B in Fig. ... With this convention, counterclockwise moments
acting on the beam are considered to be positive, and clockwise end moments ...
What people are saying - Write a review
We haven't found any reviews in the usual places.
Other editions - View all
Common terms and phrases
allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero
Bibliographic information
| Title | Strength of materials |
| Author | Ferdinand Leon Singer |
| Edition | 2 |
| Publisher | Harper, 1962 |
| Original from | the University of Michigan |
| Digitized | 29 Nov 2007 |
| Length | 590 pages |
| Subjects | Strength of materials |
| Export Citation | BiBTeX EndNote RefMan |