## Strength of materials |

### From inside the book

Results 1-3 of 89

Page 115

... and E. The moment curve between C and D is a symmetrical parabola with its

vertex at G, because at

numerically

oppositely directed.

... and E. The moment curve between C and D is a symmetrical parabola with its

vertex at G, because at

**equal**distances to either side of G the shear isnumerically

**equal**but of opposite sign, thereby producing**equal**slopesoppositely directed.

Page 160

However, the first method indicates the decreasing magnitude of the increase in

the total compressive force as we descend by

although the total compressive force increases as we descend by

...

However, the first method indicates the decreasing magnitude of the increase in

the total compressive force as we descend by

**equal**intervals from the top; i.e.,although the total compressive force increases as we descend by

**equal**intervals...

Page 227

The deviation at C from the midspan tangent drawn at B is

the actual midspan deflection in Fig. 6-27a. Since we are considering the

deviation of C from the midspan tangent drawn at B, we need the moment

diagram of ...

The deviation at C from the midspan tangent drawn at B is

**equal**to 25, or twicethe actual midspan deflection in Fig. 6-27a. Since we are considering the

deviation of C from the midspan tangent drawn at B, we need the moment

diagram of ...

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

### Common terms and phrases

allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero