Strength of Materials |
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Page 366
... equivalent wood area is n times as wide as the steel it replaces ; the equivalent wood section is shown in Fig . 10-1b . If desired , an equivalent steel section can be set up 1 by replacing the original wood by steel as wide , as in ...
... equivalent wood area is n times as wide as the steel it replaces ; the equivalent wood section is shown in Fig . 10-1b . If desired , an equivalent steel section can be set up 1 by replacing the original wood by steel as wide , as in ...
Page 370
... equivalent section of a composite beam , because its derivation was based on the difference in normal forces between two adjacent sections . Since the forces on the original composite section and on the equivalent section are the same ...
... equivalent section of a composite beam , because its derivation was based on the difference in normal forces between two adjacent sections . Since the forces on the original composite section and on the equivalent section are the same ...
Page 382
... equivalent section of concrete shown in Fig . 10-10 . Thus we obtain V [ S. = A'D ] } Ib S8 = V ( nA , ) ( d Ib ' - kd ) ( a ) where b ' is the effective width of the steel bars , equivalent to the sum of the perimeters of the steel ...
... equivalent section of concrete shown in Fig . 10-10 . Thus we obtain V [ S. = A'D ] } Ib S8 = V ( nA , ) ( d Ib ' - kd ) ( a ) where b ' is the effective width of the steel bars , equivalent to the sum of the perimeters of the steel ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ