Strength of Materials |
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Page 126
... expressed by and V = ( EY ) L M = ( ΣM ) L = ( EM ) R Ꭱ ( 4-1 ) ( 4-2 ) in which upward - acting forces or loads cause positive effects . The shear- ing force V should be computed only in terms of the forces to the left of the section ...
... expressed by and V = ( EY ) L M = ( ΣM ) L = ( EM ) R Ꭱ ( 4-1 ) ( 4-2 ) in which upward - acting forces or loads cause positive effects . The shear- ing force V should be computed only in terms of the forces to the left of the section ...
Page 198
... expressed as 1 0AB ( Area ) AE AB ΕΙ ( 6-4 ) This is the algebraic expression of Theorem I , which is stated as follows : 1 ΕΙ Theorem I : The change in slope between tangents drawn to the elastic curve at any two points A and B is ...
... expressed as 1 0AB ( Area ) AE AB ΕΙ ( 6-4 ) This is the algebraic expression of Theorem I , which is stated as follows : 1 ΕΙ Theorem I : The change in slope between tangents drawn to the elastic curve at any two points A and B is ...
Page 536
... expression of the form Sp2 dA , where p is the perpendicular distance from dA to the axis of inertia . This integral appears so frequently that it has been named moment of inertia . * Moment of inertia applied to areas has no real ...
... expression of the form Sp2 dA , where p is the perpendicular distance from dA to the axis of inertia . This integral appears so frequently that it has been named moment of inertia . * Moment of inertia applied to areas has no real ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ