Strength of Materials |
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Page 62
... fibers . Slice ( 2 ) will rotate past slice ( 1 ) until the elastic fibers joining them are deformed enough to create a resisting torque which balances the applied torque . When this happens , slices ( 1 ) and ( 2 ) will act as a rigid ...
... fibers . Slice ( 2 ) will rotate past slice ( 1 ) until the elastic fibers joining them are deformed enough to create a resisting torque which balances the applied torque . When this happens , slices ( 1 ) and ( 2 ) will act as a rigid ...
Page 129
... fiber bd is lengthened by an amount d'd and is in tension . a dx с b d R1 R2 ( a ) Neutral surface de de g h k b d ' d ( b ) Fig . 5-1 . Deformations . The plane containing fibers like ef is called the neutral surface , because such fibers ...
... fiber bd is lengthened by an amount d'd and is in tension . a dx с b d R1 R2 ( a ) Neutral surface de de g h k b d ' d ( b ) Fig . 5-1 . Deformations . The plane containing fibers like ef is called the neutral surface , because such fibers ...
Page 152
... fibers can be located at a greater distance from the neutral axis than the weaker fibers . The ideal treatment for such materials is to locate the cen- troidal or neutral axis in such a position that the ratio of the distances from it ...
... fibers can be located at a greater distance from the neutral axis than the weaker fibers . The ideal treatment for such materials is to locate the cen- troidal or neutral axis in such a position that the ratio of the distances from it ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ