## Strength of materials |

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Page 62

Imagine the shaft to consist of innumerable thin slices, each of which is rigid and

joined to adjacent slices by elastic

the elastic

Imagine the shaft to consist of innumerable thin slices, each of which is rigid and

joined to adjacent slices by elastic

**fibers**. Slice (2) will rotate past slice (1) untilthe elastic

**fibers**joining them are deformed enough to create a resisting torque ...Page 129

Somewhere between them is located

Drawing the line c'd' through /parallel to ab shows that

amount cc' and ...

**Fiber**ac at the top is shortened, and**fiber**bd at the bottom is lengthened.Somewhere between them is located

**fiber**ef, whose length is unchanged.Drawing the line c'd' through /parallel to ab shows that

**fiber**ac is shortened anamount cc' and ...

Page 152

With such a cross section, the stronger

from the neutral axis than the weaker

materials is to locate the centroidal or neutral axis in such a position that the ratio

of the ...

With such a cross section, the stronger

**fibers**can be located at a greater distancefrom the neutral axis than the weaker

**fibers**. The ideal treatment for suchmaterials is to locate the centroidal or neutral axis in such a position that the ratio

of the ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero