## Strength of Materials |

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Page 479

566 ) , the resisting couple M , composed of the tensile and compressive forces T

and C ( shown for convenience as acting through and normal to the

and the horizontal

566 ) , the resisting couple M , composed of the tensile and compressive forces T

and C ( shown for convenience as acting through and normal to the

**flanges**) ,and the horizontal

**flange**forces H which are the resultants of the shearing ...Page 480

13 – 20 , we set a moment summation about O equal to zero and obtain ( EM , = 0

] Ve = Hh The value of the

in the

13 – 20 , we set a moment summation about O equal to zero and obtain ( EM , = 0

] Ve = Hh The value of the

**flange**force H is the product of the average shear flowin the

**flange**multiplied by the length of the**flange**. Using Eq . ( a ) of Art . 13 - 7 ...Page 482

tion of the shear center is easily located . It lies between the centroid of the

section and the centroid of the

there is only one

resistance ...

tion of the shear center is easily located . It lies between the centroid of the

section and the centroid of the

**flange**that has the larger moment of inertia . Whenthere is only one

**flange**, as in the T section in Fig . 13 - 23 , if the bendingresistance ...

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### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

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### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero