## Strength of materials |

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Page 227

This M -diagram may be drawn by parts from C to B as shown in Fig. 6-27c, or

from B to C as shown in Fig. 6-27d. To facilitate understanding of Fig. 6-27d, the

This M -diagram may be drawn by parts from C to B as shown in Fig. 6-27c, or

from B to C as shown in Fig. 6-27d. To facilitate understanding of Fig. 6-27d, the

**free**-**body diagram**of the right half of the beam is also shown adjacent to it.Page 271

Thus the beam segments between points 1 and 2 and between points 2 and 3 (

hereafter referred to as spans 1 and 2 respectively) may be isolated by means of

the

Li ...

Thus the beam segments between points 1 and 2 and between points 2 and 3 (

hereafter referred to as spans 1 and 2 respectively) may be isolated by means of

the

**free**-**body diagrams**in Fig. 8-1b. The lengths of the spans (or segments) areLi ...

Page 328

SXA cos 6 Area (Ay)=A sin 6 sin $ Sy A sin 6 (c)

wedge Szy A cos 9 SyX A sin 9 Sy A sin 9 \T (d) Point diagram of forces Fig. 9-1 3

. — Variation of stress components. librium under the action of the forces arising ...

SXA cos 6 Area (Ay)=A sin 6 sin $ Sy A sin 6 (c)

**Free**-**body diagram**of forces enwedge Szy A cos 9 SyX A sin 9 Sy A sin 9 \T (d) Point diagram of forces Fig. 9-1 3

. — Variation of stress components. librium under the action of the forces arising ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero