## Strength of materials |

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Page 227

Since we are considering the deviation of C from the midspan tangent drawn at B

, we need the moment diagram of only half the beam. This M -diagram may be

drawn by parts from C to B as shown in Fig. 6-27c, or from B to C as shown in Fig.

6-27d. To facilitate understanding of Fig. 6-27d, the

half of the beam is also shown adjacent to it. Note that the midspan moment M is

found from the fact that its effect at the right end must be equal and opposite to

that ...

Since we are considering the deviation of C from the midspan tangent drawn at B

, we need the moment diagram of only half the beam. This M -diagram may be

drawn by parts from C to B as shown in Fig. 6-27c, or from B to C as shown in Fig.

6-27d. To facilitate understanding of Fig. 6-27d, the

**free**-**body diagram**of the righthalf of the beam is also shown adjacent to it. Note that the midspan moment M is

found from the fact that its effect at the right end must be equal and opposite to

that ...

Page 271

At any three points 1, 2, and 3, pass cutting sections and replace the effects of the

loads to the left or right of these sections by the proper values of vertical shear

and bending moment. Thus the beam segments between points 1 and 2 and

between points 2 and 3 (hereafter referred to as spans 1 and 2 respectively) may

be isolated by means of the

spans (or segments) are Li and L2, and the bending moments at points 1, 2, and

3 are Mi ...

At any three points 1, 2, and 3, pass cutting sections and replace the effects of the

loads to the left or right of these sections by the proper values of vertical shear

and bending moment. Thus the beam segments between points 1 and 2 and

between points 2 and 3 (hereafter referred to as spans 1 and 2 respectively) may

be isolated by means of the

**free**-**body diagrams**in Fig. 8-1b. The lengths of thespans (or segments) are Li and L2, and the bending moments at points 1, 2, and

3 are Mi ...

Page 328

SXA cos 6 Area (Ay)=A sin 6 sin $ Sy A sin 6 (c)

wedge Szy A cos 9 SyX A sin 9 Sy A sin 9 \T (d) Point diagram of forces Fig. 9-1 3

. — Variation of stress components. librium under the action of the forces arising

from the stresses that act over its faces. The area of the inclined face being

denoted by A , these forces are shown in the

point diagram of these forces is shown in Fig. 9-13d. Applying the conditions of ...

SXA cos 6 Area (Ay)=A sin 6 sin $ Sy A sin 6 (c)

**Free**-**body diagram**of forces enwedge Szy A cos 9 SyX A sin 9 Sy A sin 9 \T (d) Point diagram of forces Fig. 9-1 3

. — Variation of stress components. librium under the action of the forces arising

from the stresses that act over its faces. The area of the inclined face being

denoted by A , these forces are shown in the

**free**-**body diagram**in Fig. 9-13c. Thepoint diagram of these forces is shown in Fig. 9-13d. Applying the conditions of ...

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