## Strength of Materials |

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Page xxi

Each component reflects a different effect of the applied loads on the member

and is

measures the pulling ( or pushing ) action over the section . A pull represents a

tensile ...

Each component reflects a different effect of the applied loads on the member

and is

**given**a special name , as follows : Pix Axial force . This componentmeasures the pulling ( or pushing ) action over the section . A pull represents a

tensile ...

Page 539

The moment of inertia is

differential element has the same moment arm . The strip may be placed on

either side of the reference axis , since if k is minus , squaring it will automatically

make it ...

The moment of inertia is

**given**by I = Spa dA = kas dA = Ak2 because eachdifferential element has the same moment arm . The strip may be placed on

either side of the reference axis , since if k is minus , squaring it will automatically

make it ...

Page 558

P - A37 with respect to the

A37 . Fig . P - A38 . A38 . Use the result of Prob . A37 to determine the product of

inertia of the shaded area described in Fig . P - A38 with respect to the

and ...

P - A37 with respect to the

**given**X and Y axes . Ans . Pay = 100 Y - 이 Fig . P -A37 . Fig . P - A38 . A38 . Use the result of Prob . A37 to determine the product of

inertia of the shaded area described in Fig . P - A38 with respect to the

**given**Xand ...

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### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

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### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero