## Strength of materials |

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Page 160

Thus a larger shear resistance must be developed over the

than at dee. Of course, the total compressive force C\ plus C2 acting over the

area abgf may also be computed as the average of the stresses Sa and S/

multiplied ...

Thus a larger shear resistance must be developed over the

**horizontal**layer at fgthan at dee. Of course, the total compressive force C\ plus C2 acting over the

area abgf may also be computed as the average of the stresses Sa and S/

multiplied ...

Page 162

Derivation of Formula for

sections (1) and (2) in a beam separated by the distance dx, as shown in Fig. 5-

21, and let the shaded part between them be isolated as a free body. Fig. 5-22 is

a ...

Derivation of Formula for

**Horizontal**Shearing Stress Consider two adjacentsections (1) and (2) in a beam separated by the distance dx, as shown in Fig. 5-

21, and let the shaded part between them be isolated as a free body. Fig. 5-22 is

a ...

Page 163

... dM From Art. 4-4 we recall that — — = V, the vertical shear; so we obtain for dx

the

means the sum of the moments of the differential areas dA about the neutral axis,

...

... dM From Art. 4-4 we recall that — — = V, the vertical shear; so we obtain for dx

the

**horizontal**shearing stress, (5-4) We have replaced the integral yd A, whichmeans the sum of the moments of the differential areas dA about the neutral axis,

...

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