## Strength of materials |

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Page 100

9' 800 lb 900 lb b\ 3' 4' \b 100

. ▻ ~— 6' — 404. Beam loaded as shown in Fig. P-404. Ans. Mac = 3600 — 230x

— 30x2; Max. M = —3480 ft-lb 405. Beam loaded as shown in Fig. P-405.

9' 800 lb 900 lb b\ 3' 4' \b 100

**lb**/**ft**12' 4001b 60**lb**/**ft**12' «2 Fig. P-403. Fig. P-404. ▻ ~— 6' — 404. Beam loaded as shown in Fig. P-404. Ans. Mac = 3600 — 230x

— 30x2; Max. M = —3480 ft-lb 405. Beam loaded as shown in Fig. P-405.

Page 116

M = 5000 ft-Ib 428. In the overhanging beam shown in Fig. P-428, determine P so

that the moments over the supports equal the moment at midspan. 429. Beam

loaded as shown in Fig. P-429. Ans. Max. M = 8512.5 ft-lb 400 lb 1600 lb 200

M = 5000 ft-Ib 428. In the overhanging beam shown in Fig. P-428, determine P so

that the moments over the supports equal the moment at midspan. 429. Beam

loaded as shown in Fig. P-429. Ans. Max. M = 8512.5 ft-lb 400 lb 1600 lb 200

**lb**/**ft**...Page 223

Ans. EIS = 8000

Fig. P-654, find the value of EIS at 3

to the elastic curve at R2. 655. Find the value of EIS under each concentrated ...

Ans. EIS = 8000

**lb**-ft3 Rx R2 Fig. P-653. Fig. P-654. 654. For the beam shown inFig. P-654, find the value of EIS at 3

**ft**from R2. Hint: Draw the reference tangentto the elastic curve at R2. 655. Find the value of EIS under each concentrated ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero