## Strength of materials |

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Page 168

The shearing stress at 2 in. from the top can also be computed from Fig. 5-27d, in

which the area A' is ... As noted on page 165, this equation determines the

The shearing stress at 2 in. from the top can also be computed from Fig. 5-27d, in

which the area A' is ... As noted on page 165, this equation determines the

**maximum shearing stress**on any rectangular section. <? - 3 V ' - 2 bh. 3 1800 .Page 329

Hence, the planes I on which maximum and minimum normal stresses occur are

90° apart. \ Similarly, from Eq. (9-8) the planes on which the

Hence, the planes I on which maximum and minimum normal stresses occur are

90° apart. \ Similarly, from Eq. (9-8) the planes on which the

**maximum shearing****stress**occurs are also found to be 90° apart. The planes of zero shearing stress ...Page 461

This indicates that the maximum tensile or compressive stress alone is not

sufficient to define yielding. ... theory, the maximum shear theory assumes that

yielding begins when the

This indicates that the maximum tensile or compressive stress alone is not

sufficient to define yielding. ... theory, the maximum shear theory assumes that

yielding begins when the

**maximum shearing stress**equals the**maximum****shearing stress**...### What people are saying - Write a review

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero