## Strength of materials |

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Page 10

Determine the

0.75 in.2 A - 1.0 in. a - 0.5 in.2 ZP w 3' 4P- 5' IP 4' Fig. P-108 and P-109. 109. In

the preceding problem, find the

...

Determine the

**stress**in each material if P = 3000 lb. Bronze Aluminum Steel A -0.75 in.2 A - 1.0 in. a - 0.5 in.2 ZP w 3' 4P- 5' IP 4' Fig. P-108 and P-109. 109. In

the preceding problem, find the

**maximum**value of P that will not exceed a**stress**...

Page 80

At B, the stresses are oppositely directed, and the resultant stress is the

difference between <S2 and Si . At the inside fiber C, however, the two stresses

are collinear and in the same sense; their sum produces the

the section ...

At B, the stresses are oppositely directed, and the resultant stress is the

difference between <S2 and Si . At the inside fiber C, however, the two stresses

are collinear and in the same sense; their sum produces the

**maximum stress**inthe section ...

Page 461

This indicates that the

sufficient to define yielding. Nevertheless, this theory does give results that agree

well with test results from brittle materials. The

According to ...

This indicates that the

**maximum**tensile or compressive**stress**alone is notsufficient to define yielding. Nevertheless, this theory does give results that agree

well with test results from brittle materials. The

**Maximum**Strain Theory.According to ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero