## Strength of materials |

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Page 152

However, for materials relatively weak in tension and strong in compression,

such as cast iron, it is desirable to use beams that are unsymmetrical with respect

to the

a ...

However, for materials relatively weak in tension and strong in compression,

such as cast iron, it is desirable to use beams that are unsymmetrical with respect

to the

**neutral axis**. With such a cross section, the stronger fibers can be located ata ...

Page 160

This analysis shows that the maximum unbalanced horizontal force exists at the

layers below the

This analysis shows that the maximum unbalanced horizontal force exists at the

**neutral axis**. This unbalanced force decreases gradually to zero as the effects oflayers below the

**neutral axis**are included. This is so because the horizontal ...Page 489

From this, we see that unless Ix = Iy or tan 6 = 0 or oo, the

perpendicular to the load. Also observe, as shown in Fig. 13-28a, that the

is ...

From this, we see that unless Ix = Iy or tan 6 = 0 or oo, the

**neutral axis**is notperpendicular to the load. Also observe, as shown in Fig. 13-28a, that the

**neutral****axis**is inclined from the X axis in the same angular sense as the plane of loadingis ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero