Strength of Materials |
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Page 152
... neutral axis . With such a cross section , the stronger fibers can be located at a greater distance from the neutral axis than the weaker fibers . The ideal treatment for such materials is to locate the cen- troidal or neutral axis in ...
... neutral axis . With such a cross section , the stronger fibers can be located at a greater distance from the neutral axis than the weaker fibers . The ideal treatment for such materials is to locate the cen- troidal or neutral axis in ...
Page 160
... neutral axis . This unbalanced force decreases gradually to zero as the effects of layers below the neutral axis are included . This is so because the horizontal effect of the compressive forces is increasingly offset by the ...
... neutral axis . This unbalanced force decreases gradually to zero as the effects of layers below the neutral axis are included . This is so because the horizontal effect of the compressive forces is increasingly offset by the ...
Page 489
... neutral axis is inclined from the X axis in the same angular sense as the plane of loading is from the Y axis . To determine the deflection , we combine vectorially the deflections caused by the X and Y components of the load . These ...
... neutral axis is inclined from the X axis in the same angular sense as the plane of loading is from the Y axis . To determine the deflection , we combine vectorially the deflections caused by the X and Y components of the load . These ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ