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Page 337
... principal stresses and the maximum shearing stress . Sketch the planes on which these stresses act . STY = Ans . Max . Sn max . S = = 17,430 psi ; min . Sn 14,430 psi . = -11,430 psi ; Y 8000 6000 934. If an element is subjected to the ...
... principal stresses and the maximum shearing stress . Sketch the planes on which these stresses act . STY = Ans . Max . Sn max . S = = 17,430 psi ; min . Sn 14,430 psi . = -11,430 psi ; Y 8000 6000 934. If an element is subjected to the ...
Page 338
... principal stresses and principal planes caused by the superposition of these stresses . -26.2 ° 3000 X Ans . Max . Sn = 11,780 psi at 0 = N 4000 30 ° 4000 X X 10,000 30 ° 10,000 T ( c ) 3000 ( a ) ( b ) Fig . P - 939 and P - 940 . 940 ...
... principal stresses and principal planes caused by the superposition of these stresses . -26.2 ° 3000 X Ans . Max . Sn = 11,780 psi at 0 = N 4000 30 ° 4000 X X 10,000 30 ° 10,000 T ( c ) 3000 ( a ) ( b ) Fig . P - 939 and P - 940 . 940 ...
Page 340
... principal stresses vary with the intensities of the flexural stress S , and the horizontal shearing stress S .. For example , at point A of the cantilever beam in Fig . 9-22 , Mohr's circle shows that the direction of the principal ...
... principal stresses vary with the intensities of the flexural stress S , and the horizontal shearing stress S .. For example , at point A of the cantilever beam in Fig . 9-22 , Mohr's circle shows that the direction of the principal ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ