## Strength of Materials |

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Page 340

These deformations agree with the directions of the tensile and compressive

stresses previously obtained . ì In beams , the directions of the

vary with the intensities of the flexural stress S , and the horizontal shearing

stress ...

These deformations agree with the directions of the tensile and compressive

stresses previously obtained . ì In beams , the directions of the

**principal**stressesvary with the intensities of the flexural stress S , and the horizontal shearing

stress ...

Page 487

This integral is the product of inertia Pxy , which is zero only if X and Y are the

be applied only if the bending loads act in a longitudinal plane parallel to or ...

This integral is the product of inertia Pxy , which is zero only if X and Y are the

**principal**axes of inertia of the section . We conclude that the flexure formula maybe applied only if the bending loads act in a longitudinal plane parallel to or ...

Page 563

coordinates indicate maximum and minimum moments of inertia are located on

the I axis and have a zero product of inertia . Conversely , axes which have a

zero ...

**Principal**Axes An inspection of Mohr ' s circle will show that the points whosecoordinates indicate maximum and minimum moments of inertia are located on

the I axis and have a zero product of inertia . Conversely , axes which have a

zero ...

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### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

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### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero