## Strength of materials |

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Page 28

These conditions are: 1. The specimen must be of constant cross section. 2. The

material must be homogeneous. 3. The load must be axial, i.e., produce uniform

stress.

...

These conditions are: 1. The specimen must be of constant cross section. 2. The

material must be homogeneous. 3. The load must be axial, i.e., produce uniform

stress.

**Proportional Limit**. From the origin 0 to a point called the**proportional limit**,...

Page 394

In order for Euler's formula to be applicable, the stress accompanying the

bending which occurs during buckling must not exceed the

This stress may be found by replacing in Euler's formula the moment of inertia /

by its ...

In order for Euler's formula to be applicable, the stress accompanying the

bending which occurs during buckling must not exceed the

**proportional limit**.This stress may be found by replacing in Euler's formula the moment of inertia /

by its ...

Page 397

30-lb channels are latticed together so they have equal moments of inertia about

the principal axes. Determine the minimum length of a column having this section

, assuming pinned ends, E = 30 X 106 psi, and a

30-lb channels are latticed together so they have equal moments of inertia about

the principal axes. Determine the minimum length of a column having this section

, assuming pinned ends, E = 30 X 106 psi, and a

**proportional limit**of 35,000 psi ...### What people are saying - Write a review

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero