## Strength of Materials |

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Page 79

We then analyze the stress distribution that creates these

– 13a shows the free - body diagram of the upper half of the spring . To balance

the applied axial load P , the exposed shaded cross section of the spring must ...

We then analyze the stress distribution that creates these

**resisting**forces . Fig . 3– 13a shows the free - body diagram of the upper half of the spring . To balance

the applied axial load P , the exposed shaded cross section of the spring must ...

Page 91

To maintain equilibrium in this segment of the beam , the fibers in the exploratory

section a - a must supply the

static equilibrium . In this case , the external load is vertical , so the condition ...

To maintain equilibrium in this segment of the beam , the fibers in the exploratory

section a - a must supply the

**resisting**forces necessary to satisfy the conditions ofstatic equilibrium . In this case , the external load is vertical , so the condition ...

Page 479

The

through the web of the channel ( as shown for a WF beam in Prob . 566 ) , the

The

**resisting**forces consist of the**resisting**vertical shear V , considered as actingthrough the web of the channel ( as shown for a WF beam in Prob . 566 ) , the

**resisting**couple M , composed of the tensile and compressive forces T and C ...### What people are saying - Write a review

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### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

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### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero