## Strength of materials |

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Page 61

The first two apply only to

circular. 2. Plane sections remain plane and do not warp. 3. The projection upon

a transverse section of straight radial lines in the section remains straight. 4.

is loaded by twisting couples in planes that are perpendicular to the axis of the

Formulas Fig. 3-1 shows two views of a solid circular

at ...

The first two apply only to

**shafts**of circular section. 1. Circular sections remaincircular. 2. Plane sections remain plane and do not warp. 3. The projection upon

a transverse section of straight radial lines in the section remains straight. 4.

**Shaft**is loaded by twisting couples in planes that are perpendicular to the axis of the

**shaft**. 5. Stresses do not exceed the proportional limit. 3-2. Derivation of TorsionFormulas Fig. 3-1 shows two views of a solid circular

**shaft**. If a torque T is appliedat ...

Page 69

What is the minimum diameter of a solid steel

more than 3° in a 20-ft length when subjected to a torque of 10,000 ft-lb? What

maximum shearing stress is developed? G = 12 X 106 psi. Ana. d = 4.65 in.; S. =

6080 psi 305. A solid

4°. If G = 12 X 106 psi, compute the

1200 rpm? 306. What should be the length of a O.lO-in.-diameter bronze wire so

that it ...

What is the minimum diameter of a solid steel

**shaft**that will not twist throughmore than 3° in a 20-ft length when subjected to a torque of 10,000 ft-lb? What

maximum shearing stress is developed? G = 12 X 106 psi. Ana. d = 4.65 in.; S. =

6080 psi 305. A solid

**shaft**16 ft long is stressed to 8000 psi when twisted through4°. If G = 12 X 106 psi, compute the

**shaft**diameter. What hp can be transmitted at1200 rpm? 306. What should be the length of a O.lO-in.-diameter bronze wire so

that it ...

Page 70

313 if the

and 105 hp applied at B. 315. A 16-ft

at a gear that is 6 ft from the left end where 30 hp are removed. At the right end,

40 hp are removed and another 30 hp leaves the

a) Find the uniform

8000 psi. (b) If a uniform diameter of 4 in. is specified, determine the angle by

which one ...

313 if the

**shaft**rotates at 126 rpm with 30 hp taken off at A, 75 hp removed at C,and 105 hp applied at B. 315. A 16-ft

**shaft**rotating at 126 rpm has 100 hp appliedat a gear that is 6 ft from the left end where 30 hp are removed. At the right end,

40 hp are removed and another 30 hp leaves the

**shaft**at 5 ft from the right end. (a) Find the uniform

**shaft**diameter so that the shearing stress will not exceed8000 psi. (b) If a uniform diameter of 4 in. is specified, determine the angle by

which one ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero