## Strength of materials |

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Page 480

L= \2~2r)h = Vhtb* 4/ This value of H may now be substituted in Eq. (a), yielding

Hh _ h2b2t e - V - 4/ (13-9) Point C on the N.A. located a distance e from the

center of the web is the

13-20.

L= \2~2r)h = Vhtb* 4/ This value of H may now be substituted in Eq. (a), yielding

Hh _ h2b2t e - V - 4/ (13-9) Point C on the N.A. located a distance e from the

center of the web is the

**shear center**for the channel. h-6 3 g 1.1 H H H H H Fig.13-20.

Page 482

tion of the

and the centroid of the flange that has the larger moment of inertia. When there is

only one flange, as in the T section in Fig. 13-23, if the bending resistance of ...

tion of the

**shear center**is easily located. It lies between the centroid of the sectionand the centroid of the flange that has the larger moment of inertia. When there is

only one flange, as in the T section in Fig. 13-23, if the bending resistance of ...

Page 485

Show that the

in. and t = 0.10 in., that e = 4.78 in. Need the value of ( be specified? 1326. If the

vertical

flow ...

Show that the

**shear**tr***center**is e = — (*, + 3) to the left of 0, and hence for r = 2in. and t = 0.10 in., that e = 4.78 in. Need the value of ( be specified? 1326. If the

vertical

**shear**on the section shown in Fig. P-1326 is 576 lb, construct a**shear**flow ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero