Strength of materials |
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Page 480
L= \2~2r)h = Vhtb* 4/ This value of H may now be substituted in Eq. (a), yielding
Hh _ h2b2t e - V - 4/ (13-9) Point C on the N.A. located a distance e from the
center of the web is the shear center for the channel. h-6 3 g 1.1 H H H H H Fig.
13-20.
L= \2~2r)h = Vhtb* 4/ This value of H may now be substituted in Eq. (a), yielding
Hh _ h2b2t e - V - 4/ (13-9) Point C on the N.A. located a distance e from the
center of the web is the shear center for the channel. h-6 3 g 1.1 H H H H H Fig.
13-20.
Page 482
tion of the shear center is easily located. It lies between the centroid of the section
and the centroid of the flange that has the larger moment of inertia. When there is
only one flange, as in the T section in Fig. 13-23, if the bending resistance of ...
tion of the shear center is easily located. It lies between the centroid of the section
and the centroid of the flange that has the larger moment of inertia. When there is
only one flange, as in the T section in Fig. 13-23, if the bending resistance of ...
Page 485
Show that the shear tr* center is e = — (*, + 3) to the left of 0, and hence for r = 2
in. and t = 0.10 in., that e = 4.78 in. Need the value of ( be specified? 1326. If the
vertical shear on the section shown in Fig. P-1326 is 576 lb, construct a shear
flow ...
Show that the shear tr* center is e = — (*, + 3) to the left of 0, and hence for r = 2
in. and t = 0.10 in., that e = 4.78 in. Need the value of ( be specified? 1326. If the
vertical shear on the section shown in Fig. P-1326 is 576 lb, construct a shear
flow ...
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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero
Bibliographic information
| Title | Strength of materials |
| Author | Ferdinand Leon Singer |
| Edition | 2 |
| Publisher | Harper, 1962 |
| Original from | the University of Michigan |
| Digitized | 29 Nov 2007 |
| Length | 590 pages |
| Subjects | Strength of materials |
| Export Citation | BiBTeX EndNote RefMan |