Strength of Materials |
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Page 41
... static equilibrium are not sufficient for a solution . This con- dition exists in structures where the reactive forces or the internal resisting forces over a cross section exceed the number of independent equations of equilibrium ...
... static equilibrium are not sufficient for a solution . This con- dition exists in structures where the reactive forces or the internal resisting forces over a cross section exceed the number of independent equations of equilibrium ...
Page 246
... static equilibrium , so the beam has one redundant support . In other words , if any arbitrary value is assumed for R , values of V and M may be computed that will satisfy the equations of static equilibrium . Determination of the ...
... static equilibrium , so the beam has one redundant support . In other words , if any arbitrary value is assumed for R , values of V and M may be computed that will satisfy the equations of static equilibrium . Determination of the ...
Page 456
... static failure of a brittle material . At first it was thought that repeated applications of the load changed the crystalline structure of the material , but we now know that this is not true . Fatigue failure is explained more ...
... static failure of a brittle material . At first it was thought that repeated applications of the load changed the crystalline structure of the material , but we now know that this is not true . Fatigue failure is explained more ...
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allowable stresses aluminum angle applied assumed axial load beam in Fig beam loaded beam shown bending bending moment bolt bronze cantilever beam caused centroid column compressive stress Compute the maximum concentrated load concrete continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS inertia lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan deflection modulus Mohr's circle moment of area moment of inertia neutral axis obtain plane positive proportional limit R₂ radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear diagram shearing force shown in Fig Solution Solve Prob span statically indeterminate steel strain tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld zero ΕΙ