## Strength of materials |

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Page 15

The bearing resistance at the girder depends on the minimum

connection, which in this case is the f-in.

8 field-driven rivets in bearing: [P - AS] 77777. P = 8(f) (f) (20,000) = 45,000lb f • t

...

The bearing resistance at the girder depends on the minimum

**thickness**of theconnection, which in this case is the f-in.

**thickness**of the clip angle. We obtain for8 field-driven rivets in bearing: [P - AS] 77777. P = 8(f) (f) (20,000) = 45,000lb f • t

...

Page 76

3-9a we consider a tube of arbitrary shape with a variable wall

is relatively small compared with the dimensions of the cross section. Fig. 3-9b

shows, enlarged, a free body of a Fig. 3-9. — Shear flow in a thin-walled tube.

3-9a we consider a tube of arbitrary shape with a variable wall

**thickness**t whichis relatively small compared with the dimensions of the cross section. Fig. 3-9b

shows, enlarged, a free body of a Fig. 3-9. — Shear flow in a thin-walled tube.

Page 431

1203. A double-riveted lap joint forms the girth seam of a boiler 5 ft in diameter.

Pitch of the rivets is 3^ in., diameter of rivet hole is \% in.,

in. Find the strength of a repeating section, the efficiency, and maximum internal ...

1203. A double-riveted lap joint forms the girth seam of a boiler 5 ft in diameter.

Pitch of the rivets is 3^ in., diameter of rivet hole is \% in.,

**thickness**of plate is y$in. Find the strength of a repeating section, the efficiency, and maximum internal ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero