## Strength of Materials |

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Page 90

It may be distributed

part of the length , as in Fig . 4 - 1c . Distributed loads may also be

varying or nonuniform . In a

loading ...

It may be distributed

**uniformly**over the entire length , as in Fig . 4 - 1b , or overpart of the length , as in Fig . 4 - 1c . Distributed loads may also be

**uniformly**varying or nonuniform . In a

**uniformly**varying or triangular load , the intensity ofloading ...

Page 111

Replacing the

and equating moments about Ri to zero ... Dividing R2 by the length of 4 ft over

which it is assumed to be

Replacing the

**uniformly**distributed reaction between C and D by its resultant R2and equating moments about Ri to zero ... Dividing R2 by the length of 4 ft over

which it is assumed to be

**uniformly**distributed gives the upward intensity of this ...Page 447

This analysis was based on the concept that the weld is

its length . This assumption is reasonable if all welds are of the same size and if

the applied load passes through the centroid of the weld lines . If the resultant

load ...

This analysis was based on the concept that the weld is

**uniformly**loaded alongits length . This assumption is reasonable if all welds are of the same size and if

the applied load passes through the centroid of the weld lines . If the resultant

load ...

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### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

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### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero