## Strength of Materials |

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Page 172

No principles are required beyond those already developed . In heavily loaded

short beams , the design is usually governed by the shearing stress ( which

because ...

No principles are required beyond those already developed . In heavily loaded

short beams , the design is usually governed by the shearing stress ( which

**varies**with V ) ; but in longer beams , the flexure stress generally governs ,because ...

Page 275

Uniformly

span L in a continuous beam

assumed to be supported on a simple span , the moment diagram is drawn by

parts ...

Uniformly

**varying**load . Case 3 . Uniformly**Varying**Load . The loading over aspan L in a continuous beam

**varies**uniformly over the span . If this loading isassumed to be supported on a simple span , the moment diagram is drawn by

parts ...

Page 310

856 if the moment of inertia

for span 1 is 2 , that for span 2 is 1 . 5 , and that for span 3 is 1 . 886 . Solve for the

support moments in Prob . 825 ( page 284 ) if the ends are perfectly fixed ...

856 if the moment of inertia

**varies**from span to span so that the relative stiffnessfor span 1 is 2 , that for span 2 is 1 . 5 , and that for span 3 is 1 . 886 . Solve for the

support moments in Prob . 825 ( page 284 ) if the ends are perfectly fixed ...

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### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

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### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero