Strength of materials |
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Page 91
To satisfy 2F = 0, the vertical unbalance caused by Ri requires the fibers in
section a-a to create a resisting force. This is shown as Vr, and is called the
resisting shearing force. For the loading shown, VT is numerically equal to Ri; but
if ...
To satisfy 2F = 0, the vertical unbalance caused by Ri requires the fibers in
section a-a to create a resisting force. This is shown as Vr, and is called the
resisting shearing force. For the loading shown, VT is numerically equal to Ri; but
if ...
Page 104
Hence, as is shown in the composite figure (e), the effect of the loads at one side
of an exploratory section reduces to a system of forces whose vertical summation
is the vertical shear and a system of couples whose algebraic summation is the ...
Hence, as is shown in the composite figure (e), the effect of the loads at one side
of an exploratory section reduces to a system of forces whose vertical summation
is the vertical shear and a system of couples whose algebraic summation is the ...
Page 164
vertical shearing stress. It is this vertical shearing stress S,v, shown in Fig. 5-23,
that forms the resisting vertical shear Vr = fS, dA which balances the vertical
shear V. Since it is not feasible to determine S,v directly, we have resorted to
deriving ...
vertical shearing stress. It is this vertical shearing stress S,v, shown in Fig. 5-23,
that forms the resisting vertical shear Vr = fS, dA which balances the vertical
shear V. Since it is not feasible to determine S,v directly, we have resorted to
deriving ...
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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero
Bibliographic information
| Title | Strength of materials |
| Author | Ferdinand Leon Singer |
| Edition | 2 |
| Publisher | Harper, 1962 |
| Original from | the University of Michigan |
| Digitized | 29 Nov 2007 |
| Length | 590 pages |
| Subjects | Strength of materials |
| Export Citation | BiBTeX EndNote RefMan |