## Strength of Materials |

### From inside the book

Results 1-3 of 61

Page 28

( 2 )

material without any corresponding increase of load ; indeed , the load may

actually decrease while the

( 2 )

**Yield**point , at which there is an appreciable elongation or**yielding**of thematerial without any corresponding increase of load ; indeed , the load may

actually decrease while the

**yielding**occurs . However , the phenomenon of**yielding**is ...Page 511

Until the shear

distribution shown in Fig . 14 – 2a . At the beginning of

given by Typ = 57 Soup ( a ) If we twist the shaft beyond this point , the shearing ...

Until the shear

**yield**point Sey is reached , the bar is elastic and has the stressdistribution shown in Fig . 14 – 2a . At the beginning of

**yielding**, the torque isgiven by Typ = 57 Soup ( a ) If we twist the shaft beyond this point , the shearing ...

Page 513

If the

? Ans . ri = 1 . 27 in . 1402 . Determine the ratio of the limit torque to the

torque in a hollow circular shaft whose outer radius is twice the inner radius .

If the

**yield**stress is Sayo = 20 , 000 psi , to what radius does elastic action extend? Ans . ri = 1 . 27 in . 1402 . Determine the ratio of the limit torque to the

**yield**torque in a hollow circular shaft whose outer radius is twice the inner radius .

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Contents

List of Symbols and Abbreviations | xvi |

SIMPLE STRAIN | 26 |

TORSION | 60 |

Copyright | |

18 other sections not shown

### Other editions - View all

### Common terms and phrases

acting actual allowable angle applied assumed axes axial axis beam beam shown bending bending moment cantilever carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum maximum shearing method midspan moments negative neutral axis normal obtain occurs plane plate positive principal Prob PROBLEMS produce radius reaction reduces reference reinforced relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows slope Solution Solve span steel strain strength supported Table tangent tensile thickness torsional uniformly varies vertical weight weld yield zero