Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 297
... circuit . If the flux through C is constant so that dP / dt = 0 , then it is found that there is no current in the circuit . Faraday found , however , that if the flux through C is not constant , so that do / dt 0 , then there is a ...
... circuit . If the flux through C is constant so that dP / dt = 0 , then it is found that there is no current in the circuit . Faraday found , however , that if the flux through C is not constant , so that do / dt 0 , then there is a ...
Page 299
... circuit C will then be the rectangle of sides / and x . Let us choose the sense of traversal about C to be counterclockwise , so that the positive sense of the area is out of the paper . Then the flux through C as found from ( 16-6 ) is ...
... circuit C will then be the rectangle of sides / and x . Let us choose the sense of traversal about C to be counterclockwise , so that the positive sense of the area is out of the paper . Then the flux through C as found from ( 16-6 ) is ...
Page 327
... circuit is being translated by this amount but is not rotated . The other circuit C ' is held fixed , as are the batteries responsible for the maintenance of the currents . ( Consequently , we will never be able to treat these circuits ...
... circuit is being translated by this amount but is not rotated . The other circuit C ' is held fixed , as are the batteries responsible for the maintenance of the currents . ( Consequently , we will never be able to treat these circuits ...
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Common terms and phrases
Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх