## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 297

The flux through this

of the element of area da by Figure 1-24 and we can then find <I> from (16-6); <1)

will be positive for the choice shown in the figure. We assume that there are no ...

The flux through this

**circuit**is positive. by the arrow, this will define the directionof the element of area da by Figure 1-24 and we can then find <I> from (16-6); <1)

will be positive for the choice shown in the figure. We assume that there are no ...

Page 299

The

of traversal about C to be counterclockwise, so that the positive sense of the area

is out of the paper. Then the flux through C as found from (16-6) is <l>=fB-da=BIx

...

The

**circuit**C will then be the rectangle of sides l and x. Let us choose the senseof traversal about C to be counterclockwise, so that the positive sense of the area

is out of the paper. Then the flux through C as found from (16-6) is <l>=fB-da=BIx

...

Page 327

18-3 Magnetic Forces on Clrcults As we know, two current carrying

general exert forces on each other and, in principle, these forces can be

calculated from Ampére's law. However, as we saw for electrostatic forces in

Section 7-4, ...

18-3 Magnetic Forces on Clrcults As we know, two current carrying

**circuits**will ingeneral exert forces on each other and, in principle, these forces can be

calculated from Ampére's law. However, as we saw for electrostatic forces in

Section 7-4, ...

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amplitude angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb’s law cross section current density current element cylinder defined dielectric displacement distance electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point Flgure flux force free currents frequency function Galilean transformation given incident induction infinitely long integral integrand length located loop Lorentz Lorentz transformation magnetic dipole magnitude material Maxwell’s equations medium normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector produced quadrupole quantities radiation radius rectangular reﬂected region relation result rotation satisfy scalar potential shown in Figure solenoid sphere substitute surface charge surface current tangential components transformation unit vacuum vector potential velocity volume write written xy plane zero