Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 229
... current which is called an ampere , so that , according to ( 12-1 ) , 1 coulomb = 1 ampere - second . The ampere itself is defined in terms of the force between currents ... current density and element of CURRENT AND CURRENT DENSITIES 229.
... current which is called an ampere , so that , according to ( 12-1 ) , 1 coulomb = 1 ampere - second . The ampere itself is defined in terms of the force between currents ... current density and element of CURRENT AND CURRENT DENSITIES 229.
Page 354
... current density Jm distributed throughout the volume and a surface current density K , on the bounding surface where m J = V'XM Km = MXÔ ' ( 20-7 ) ( 20-8 ) A ( r ) = Na Sv . Мо 4π Jm ( r ) dr ' Мо Km ( r ' ) da ' + ( 20-9 ) R 4π JS ' R ...
... current density Jm distributed throughout the volume and a surface current density K , on the bounding surface where m J = V'XM Km = MXÔ ' ( 20-7 ) ( 20-8 ) A ( r ) = Na Sv . Мо 4π Jm ( r ) dr ' Мо Km ( r ' ) da ' + ( 20-9 ) R 4π JS ' R ...
Page 398
... density written as the sum of the free and bound charge densities as we found in ( 10-38 ) . Similarly , the term in parentheses of ( 21-33 ) represents the total current density Jot . The first two parts are clearly the free current ...
... density written as the sum of the free and bound charge densities as we found in ( 10-38 ) . Similarly , the term in parentheses of ( 21-33 ) represents the total current density Jot . The first two parts are clearly the free current ...
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Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх