Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 251
... element Ids by the current element I'ds ' . We could call this still another version of Ampère's law and , in fact , this is very often what is done . As we pointed out , it ... CURRENT ELEMENTS 251 13-3 The Force between Current Elements.
... element Ids by the current element I'ds ' . We could call this still another version of Ampère's law and , in fact , this is very often what is done . As we pointed out , it ... CURRENT ELEMENTS 251 13-3 The Force between Current Elements.
Page 256
... current element there to have a force on it . Again , as for E , one can regard this as all simply a mathematical ... current element I , ds ; the ith circuit . We note that Ids of C is not included in ( 14-4 ) , that is , we do not ...
... current element there to have a force on it . Again , as for E , one can regard this as all simply a mathematical ... current element I , ds ; the ith circuit . We note that Ids of C is not included in ( 14-4 ) , that is , we do not ...
Page 532
... current element Ids , at ds2 can thus be written as dE : = iμlow [ I ] 4πr ( ds , Xî ) Xî ( 27-105 ) where [ 1 ] is the current evaluated at the retarded time . Now the tangential components of this electric field are continuous across ...
... current element Ids , at ds2 can thus be written as dE : = iμlow [ I ] 4πr ( ds , Xî ) Xî ( 27-105 ) where [ 1 ] is the current evaluated at the retarded time . Now the tangential components of this electric field are continuous across ...
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Common terms and phrases
Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх