Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
From inside the book
Results 1-3 of 64
Page 3
... displacement and is characterized by both a magnitude ( its length ) and a direction ( from P , to P2 ) . If we now further displace our point along E from P2 to still another point P3 , we see from Figure 1-2 that the new net effect is ...
... displacement and is characterized by both a magnitude ( its length ) and a direction ( from P , to P2 ) . If we now further displace our point along E from P2 to still another point P3 , we see from Figure 1-2 that the new net effect is ...
Page 14
... displacement . In order to understand the meaning of the gradient , let us consider Figure 1-18 , in which is indicated a series of surfaces each of which is made up of those points for which u has the same value ; in other words ...
... displacement . In order to understand the meaning of the gradient , let us consider Figure 1-18 , in which is indicated a series of surfaces each of which is made up of those points for which u has the same value ; in other words ...
Page 35
... displacement of the electron will then be parallel to Ep . The problem then reduces to a one - dimensional one and if we let x be the displacement , we can write ( B - 76 ) as me d2x + Y dt2 dx dt + wo3x ) = − eE2 = − e Epoe ' i ( kz ...
... displacement of the electron will then be parallel to Ep . The problem then reduces to a one - dimensional one and if we let x be the displacement , we can write ( B - 76 ) as me d2x + Y dt2 dx dt + wo3x ) = − eE2 = − e Epoe ' i ( kz ...
Other editions - View all
Common terms and phrases
Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх