Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 261
At large distances from the circle, that is, for z>>a, (14-18) approximates to I 'a2
13(1): “Z 3 2 (14-20) z and varies inversely as the cube of the distance z. In this
respect, it is similar to the electric field of a dipole as we saw in (10-35), for
example ...
At large distances from the circle, that is, for z>>a, (14-18) approximates to I 'a2
13(1): “Z 3 2 (14-20) z and varies inversely as the cube of the distance z. In this
respect, it is similar to the electric field of a dipole as we saw in (10-35), for
example ...
Page 480
(In radio transmission, the distance between the point of origin and return is
called the “skip distance,” and it can be many hundreds of kilometers.) In effect,
the incident wave has been “reflected” from the plasma. At the distance z,,,, 0,,(z,,,
)=90° ...
(In radio transmission, the distance between the point of origin and return is
called the “skip distance,” and it can be many hundreds of kilometers.) In effect,
the incident wave has been “reflected” from the plasma. At the distance z,,,, 0,,(z,,,
)=90° ...
Page 570
It is helpful to express our results in terms of the distance r from the charge and
the angle 0 made by r with the direction of the velocity. We see from the figure
that x = rcos0 whiley2+ z2= r2sin20 so that y2x2+y2+z2=rLy2(1—B2sin20) (28-
150) ...
It is helpful to express our results in terms of the distance r from the charge and
the angle 0 made by r with the direction of the velocity. We see from the figure
that x = rcos0 whiley2+ z2= r2sin20 so that y2x2+y2+z2=rLy2(1—B2sin20) (28-
150) ...
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amplitude angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb’s law cross section current density current element cylinder defined dielectric displacement distance electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point Flgure flux force free currents frequency function Galilean transformation given incident induction infinitely long integral integrand length located loop Lorentz Lorentz transformation magnetic dipole magnitude material Maxwell’s equations medium normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector produced quadrupole quantities radiation radius rectangular reflected region relation result rotation satisfy scalar potential shown in Figure solenoid sphere substitute surface charge surface current tangential components transformation unit vacuum vector potential velocity volume write written xy plane zero