## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 123

7-4 Find the

what should your result reduce when n=0? Does it? 7-5 Find the

charge distribution of Exercise 5-17 by using (7-8). 7-6 Find the

length ...

7-4 Find the

**energy**of the charge distribution of Exercise 5-9 by using (7-10). Towhat should your result reduce when n=0? Does it? 7-5 Find the

**energy**of thecharge distribution of Exercise 5-17 by using (7-8). 7-6 Find the

**energy**of alength ...

Page 320

It also takes work to produce a given set of currents in circuits and our aim here is

to find it and thus be able to assign a magnetic

magnetic case, however, we do not have the analogue of the point charge of ...

It also takes work to produce a given set of currents in circuits and our aim here is

to find it and thus be able to assign a magnetic

**energy**to the system. In themagnetic case, however, we do not have the analogue of the point charge of ...

Page 328

Roald K. Wangsness. éiil "'- r—>-—— .__- '—' —a—_.__ _ their

dUB = — dWm= — (Id<I>+ I'd<I>') = —2dU,,, (18-38) which is opposite in sign to

that of the circuits and twice as great in magnitude. Substituting this into (18-37), ...

Roald K. Wangsness. éiil "'- r—>-—— .__- '—' —a—_.__ _ their

**energy**, we getdUB = — dWm= — (Id<I>+ I'd<I>') = —2dU,,, (18-38) which is opposite in sign to

that of the circuits and twice as great in magnitude. Substituting this into (18-37), ...

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amplitude angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb’s law cross section current density current element cylinder defined dielectric displacement distance electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point Flgure flux force free currents frequency function Galilean transformation given incident induction infinitely long integral integrand length located loop Lorentz Lorentz transformation magnetic dipole magnitude material Maxwell’s equations medium normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector produced quadrupole quantities radiation radius rectangular reﬂected region relation result rotation satisfy scalar potential shown in Figure solenoid sphere substitute surface charge surface current tangential components transformation unit vacuum vector potential velocity volume write written xy plane zero