Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 104
... equal and opposite to the charge on the other . Accordingly , we take for our general definition of a capacitor the following : any two conductors with equal and opposite charges Q and Q. Even so , it is not immediately evident that one ...
... equal and opposite to the charge on the other . Accordingly , we take for our general definition of a capacitor the following : any two conductors with equal and opposite charges Q and Q. Even so , it is not immediately evident that one ...
Page 181
... equal the vacuum value : D = Do = 0f ( 10-61 ) This result is also consistent with ( 10-42 ) since the fields are zero inside the conducting plate and therefore D2n− D1n = D − 0 = 0 . The electric field has changed , however , since ...
... equal the vacuum value : D = Do = 0f ( 10-61 ) This result is also consistent with ( 10-42 ) since the fields are zero inside the conducting plate and therefore D2n− D1n = D − 0 = 0 . The electric field has changed , however , since ...
Page 403
... equal and opposite , that is , they are in agreement with Newton's third law . On the other hand , we found in ( 13-19 ) that the forces between current elements as given by ( 13-17 ) are not generally equal and opposite so that these ...
... equal and opposite , that is , they are in agreement with Newton's third law . On the other hand , we found in ( 13-19 ) that the forces between current elements as given by ( 13-17 ) are not generally equal and opposite so that these ...
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Common terms and phrases
Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх