Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
From inside the book
Results 1-3 of 47
Page 297
... flux through C is constant so that dP / dt = 0 , then it is found that there is no current in the circuit . Faraday found , however , that if the flux through C is not constant , so that do / dt 0 , then there is a current produced in C ...
... flux through C is constant so that dP / dt = 0 , then it is found that there is no current in the circuit . Faraday found , however , that if the flux through C is not constant , so that do / dt 0 , then there is a current produced in C ...
Page 312
... flux ; in C , that can be found from ( 16-6 ) . For our purposes , however , it will be more useful to express the flux in terms of the vector potential by means of ( 16-23 ) . Therefore , if A ( r ) is the vector potential produced by ...
... flux ; in C , that can be found from ( 16-6 ) . For our purposes , however , it will be more useful to express the flux in terms of the vector potential by means of ( 16-23 ) . Therefore , if A ( r ) is the vector potential produced by ...
Page 313
... flux through C , by a current Io in C equals the flux through Ck by the same current I。 in C ̧ . It can be seen from ( 17-46 ) that the mutual inductance can be either positive or negative depending on the choices made for the senses ...
... flux through C , by a current Io in C equals the flux through Ck by the same current I。 in C ̧ . It can be seen from ( 17-46 ) that the mutual inductance can be either positive or negative depending on the choices made for the senses ...
Other editions - View all
Common terms and phrases
Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх